| 1 | \documentclass{article} |
|---|
| 2 | \usepackage{fullpage} |
|---|
| 3 | \newcommand{\PSbox}[3]{\mbox{\rule{0in}{#3}\special{psfile=#1}\hspace{#2}}} |
|---|
| 4 | \begin{document} |
|---|
| 5 | \begin{enumerate} |
|---|
| 6 | \item Diffusion of water vapor into a flowing adhesive sheet |
|---|
| 7 | |
|---|
| 8 | \begin{enumerate} |
|---|
| 9 | \item Time required to flow down the exposed length is that length divided by |
|---|
| 10 | velocity on top of the film, which is the maximum velocity: |
|---|
| 11 | $t=L_{exp}/u_{max}$. Taking $x$ as the flow direction and $y$ as the |
|---|
| 12 | distance from the top surface, maximum velocity is given by: |
|---|
| 13 | $$u_{max} = u_x|{y=0} = \frac{\rho g\sin\theta L^2}{2\mu} = |
|---|
| 14 | \frac{\rm1060\frac{kg}{m^3}\cdot9.8\frac{m}{s^2}\cdot0.707\cdot(0.005m)^2} |
|---|
| 15 | {\rm2\cdot1\frac{kg}{m\cdot s}} = 0.0918\frac{\rm m}{\rm s}.$$ |
|---|
| 16 | $$t = \frac{L_{exp}}{u_{max}} = \frac{\rm0.05m}{\rm0.0918\frac{m}{s}} = |
|---|
| 17 | 0.545{\rm seconds}.$$ |
|---|
| 18 | |
|---|
| 19 | Is flow laminar? Check the Reynolds number using |
|---|
| 20 | $u_{av}=\frac{2}{3}u_{max}$ as the velocity: |
|---|
| 21 | $$Re = \frac{\rho u_{av}L}{\mu} = |
|---|
| 22 | \frac{\rm1060\frac{kg}{m^3}\cdot0.0612\frac{m}{s}\cdot0.005m} |
|---|
| 23 | {\rm1\frac{kg}{m\cdot s}}=0.324.$$ |
|---|
| 24 | Since this is below 20, we're well within the laminar flow r\'{e}gime. |
|---|
| 25 | |
|---|
| 26 | \item For an order of magnitude, one can just estimate the diffusion length |
|---|
| 27 | using: |
|---|
| 28 | $$L_D \simeq \sqrt{Dt} = \sqrt{\rm10^{-9}\frac{m^2}{s}\cdot0.545s} = |
|---|
| 29 | 2.3\times10^{-5}{\rm m}.$$ |
|---|
| 30 | About 20 microns, which is quite shallow. Even if a small amount of water |
|---|
| 31 | diffuses several times more deeply, this is still well within the top |
|---|
| 32 | region with roughly uniform velocity. |
|---|
| 33 | |
|---|
| 34 | \item To determine the rate-limiting step, check the Biot number, using the |
|---|
| 35 | diffusion depth as the lengthscale: |
|---|
| 36 | $${\rm Bi} = \frac{k''L}{D} = |
|---|
| 37 | \frac{\rm5\frac{m}{s}\cdot2.3\times10^{-5}m}{\rm10^{-9}\frac{m^2}{s}} |
|---|
| 38 | \simeq10^5.$$ |
|---|
| 39 | There's no question this is diffusion-limited. |
|---|
| 40 | |
|---|
| 41 | \item Your sketches should have looked something like: |
|---|
| 42 | \begin{center} |
|---|
| 43 | \PSbox{adhesiflow.ps}{204pt}{230pt} |
|---|
| 44 | \end{center} |
|---|
| 45 | |
|---|
| 46 | \item Since this is cleary diffusion-limited, the top surface will rapidly |
|---|
| 47 | reach equilibrium with the air, giving a constant top surface concentration |
|---|
| 48 | of water. The initial condition has a uniform (and hopefully low) |
|---|
| 49 | concentration of water. |
|---|
| 50 | |
|---|
| 51 | Since the diffusion depth is tiny compared to the adhesive film thickness, |
|---|
| 52 | and the top surface is a free surface where $\partial u_x/\partial y=0$, |
|---|
| 53 | the velocity is roughly uniform and equal to $u_{max}$ throughout the |
|---|
| 54 | diffusion boundary layer. |
|---|
| 55 | |
|---|
| 56 | These and the much thinner boundary layer thickness than exposed surface |
|---|
| 57 | length $\delta_C\ll L_{exp}$, give us the conditions for using the error |
|---|
| 58 | function to describe diffusion in the $y$-direction from the top, with time |
|---|
| 59 | replaced by exposure time $t=x/u_{max}$. Since the surface concentration |
|---|
| 60 | is higher than the inital concentration, it is convenient to use the erfc |
|---|
| 61 | form: |
|---|
| 62 | $$\frac{C-C_{init}}{C_S-C_{init}} = |
|---|
| 63 | {\rm erfc}\left(\frac{y}{2\sqrt{Dx/u_{max}}}\right).$$ |
|---|
| 64 | \end{enumerate} |
|---|
| 65 | \end{enumerate} |
|---|
| 66 | \end{document} |
|---|