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Revision 130, 1.2 kB
(checked in by powell, 5 years ago)
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New problem: Laminar and turbulent boundary layers
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Property svn:keywords set to
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| 1 | \documentclass{article} |
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| 2 | \usepackage{fullpage} |
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| 3 | \newcommand{\PSbox}[3]{\mbox{\rule{0in}{#3}\special{psfile=#1}\hspace{#2}}} |
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| 4 | \begin{document} |
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| 5 | \begin{enumerate} |
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| 6 | \item Laminar and turbulent boundary layers |
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| 7 | |
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| 8 | \begin{enumerate} |
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| 9 | \item Your velocity boundary layer sketch should have looked something like: |
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| 10 | \begin{center} |
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| 11 | \PSbox{boundlamturb.ps}{420pt}{128pt} |
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| 12 | \end{center} |
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| 13 | |
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| 14 | \item For laminar flow, $\delta_u\propto x^{0.5}$; for turbulent flow, |
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| 15 | $\delta_u\propto x^{0.8}$. The turbulent boundary layer grows faster |
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| 16 | because the turbulent eddies mix momentum much more effectively than |
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| 17 | viscosity ``diffuses'' it. |
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| 18 | |
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| 19 | \item If the flow can be made laminar at a given Reynolds number, the drag |
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| 20 | force will be lower than for turbulent flow. This is evident from the $f$ |
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| 21 | vs. Reynolds number curve for flow past a flat plate. |
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| 22 | |
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| 23 | Note that some people were confused by the decreasing nature of the $f$ |
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| 24 | vs. Re curve. Although $f$ is decreasing with $Re$, drag force is |
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| 25 | proportional to $fK=f\cdot\frac{1}{2}\rho U^2$, so for a given fluid and |
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| 26 | plate, drag force will increase with Reynolds number. |
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| 27 | \end{enumerate} |
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| 28 | \end{enumerate} |
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| 29 | \end{document} |
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