| 1 | \documentclass{article} |
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| 2 | \usepackage{fullpage,lmodern} |
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| 3 | \usepackage[T1]{fontenc} |
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| 4 | \begin{document} |
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| 5 | \begin{enumerate} |
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| 6 | \item Freezing Lake |
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| 7 | |
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| 8 | A shallow (10 cm deep) body of water initially at 10$^\circ$C is exposed to |
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| 9 | air at -10$^\circ$C, and begins to freeze from the top. Here we will use the |
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| 10 | finite difference method to calculate the temperature profile across the |
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| 11 | liquid water and ice, and model the growth of the ice as well as the heat |
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| 12 | conduction. We will neglect buoyancy instabilities in the water and treat it |
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| 13 | as stagnant, and also neglect the small change in overall thickness due to |
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| 14 | the lower density of ice. |
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| 15 | |
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| 16 | \noindent Properties: |
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| 17 | \begin{center} |
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| 18 | \begin{tabular}{l|c|c|} |
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| 19 | Material & Liq. water & Sol. water \\ \hline |
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| 20 | Conductivity $k$, $\rm\frac{W}{m\cdot K}$ & 0.56 & 2.3 \\ |
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| 21 | Heat capacity $c_p$, $\rm\frac{J}{kg\cdot K}$ & 4200 & 2100 \\ |
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| 22 | Density $\rho$, $\rm\frac{kg}{m^3}$ & 1000 & 920 \\ |
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| 23 | Heat of fusion $\Delta H_f$, $\rm\frac{J}{kg}$ & |
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| 24 | \multicolumn{2}{|c|}{334,000} \\ \hline |
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| 25 | \end{tabular} |
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| 26 | \end{center} |
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| 27 | |
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| 28 | |
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| 29 | |
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| 30 | |
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| 31 | |
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| 32 | \begin{enumerate} |
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| 33 | \item Write the difference equation corresponding to the following |
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| 34 | differential equation at an internal node using the forward Euler |
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| 35 | algorithm: |
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| 36 | $$\frac{\partial H}{\partial t} - |
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| 37 | \frac{\partial}{\partial x}\left(k\frac{\partial T}{\partial x}\right) =0$$ |
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| 38 | You can ``close'' this equation in your finite difference calculation by |
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| 39 | creating separate arrays to hold enthalpy and temperature, so $T_{i,n}$ is |
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| 40 | calculated from $H_{i,n}$, and $H_{i,n+1}$ is calculated from $T_{i,n}$ and |
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| 41 | its spatial neighbors. |
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| 42 | |
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| 43 | \item At the bottom of the lake ($x=10$cm), we will assume that the lake bed |
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| 44 | is a perfect insulator, so the boundary condition is equivalent to a {\em |
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| 45 | symmetry plane}. At the top surface ($x=0$), the heat flux is given by a |
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| 46 | heat transfer coefficient: $q_x = h(T_{\rm air}-T_{\rm water})$. |
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| 47 | |
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| 48 | Write the difference equations for the top and bottom finite difference |
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| 49 | nodes in your system. |
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| 50 | |
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| 51 | \item Calculate the thermal diffusivities of liquid and solid water. Which |
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| 52 | one will determine the largest stable timestep size using the forward Euler |
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| 53 | ({\em i.e.} explicit) algorithm? |
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| 54 | |
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| 55 | \item Estimate the following three timescales: |
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| 56 | \begin{enumerate} |
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| 57 | \item Time required to reach steady-state by conduction through 10 cm of |
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| 58 | liquid water. |
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| 59 | \item \label{condlimit} Time required for {\em conduction}-limited freezing |
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| 60 | of the whole lake, assuming ice is at the air temperature at the top |
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| 61 | surface and temperature profile across the ice is linear. |
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| 62 | \item \label{convlimit} Time required for {\em convection}-limited freezing |
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| 63 | of the whole lake, assuming the ice is always at its melting point. |
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| 64 | \end{enumerate} |
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| 65 | |
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| 66 | For \ref{condlimit} and \ref{convlimit}, you can model the freezing process |
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| 67 | by setting the heat flux required to freeze at a certain rate equal to the |
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| 68 | heat flux due to conduction or convection: |
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| 69 | $$\rho\Delta H_f\frac{dX}{dt} = k\frac{\Delta T}{X} {\rm or} = h\Delta T$$ |
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| 70 | and solve the resulting differential equation to determine thickness frozen |
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| 71 | $X$ vs. time $t$. |
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| 72 | |
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| 73 | \item Using at least ten nodes in the $x$-direction, perform a finite |
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| 74 | difference calculation to predict the temperature profiles throughout the |
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| 75 | freezing process with a top heat transfer coefficient of |
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| 76 | 10$\rm\frac{W}{m^2\cdot K}$. Provide plots at the times when the top of |
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| 77 | the lake just starts to freeze, when the lake is half frozen, and when the |
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| 78 | lake has just finished freezing.\footnote{This calculation can be performed |
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| 79 | in a spreadsheet, but due to the large number of timesteps required and |
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| 80 | the computational inefficiency of spreadsheets, it may take a long time |
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| 81 | to run; a C, FORTRAN or Matlab implementation will run several times |
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| 82 | faster.} |
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| 83 | \end{enumerate} |
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| 84 | \end{enumerate} |
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| 85 | \end{document} |
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| 86 | |
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| 87 | |
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| 88 | |
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